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GATE & IES — MECHANICAL ENGINEERING
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Theory of Machines

Mobility and Degrees of Freedom

Principles of mobility and degrees of freedom for Mechanical Engineering and GATE & IES preparation.

Preparation Mode
10 Active Questions
Answers & Explanations Included
šŸ“– Study the questions before taking the quiz examination. No timer • No attempt recorded • No marks awarded
Question 1 of 10
Original Exam: GATE ME (2008)
A planar mechanism has 8 links and 10 rotary joints. The number of degrees of freedom using Gruebler's criterion is:
āœ“ Correct Answer: B
Explanation:
For a planar mechanism with only lower pairs, F = 3(nāˆ’1) āˆ’ 2j. Hence F = 3(8āˆ’1) āˆ’ 2(10) = 21āˆ’20 = 1. Verified as GATE ME 2008.
Difficulty: basic Type: numerical
Question 2 of 10
Original Exam: GATE ME (2005)
The number of degrees of freedom of a planar linkage with 8 links and 9 simple revolute joints is:
āœ“ Correct Answer: C
Explanation:
Using F = 3(nāˆ’1) āˆ’ 2j, F = 3(8āˆ’1) āˆ’ 2(9) = 21āˆ’18 = 3. Verified as GATE ME 2005.
Difficulty: basic Type: numerical
Question 3 of 10
Original Exam: GATE ME (2016)
The number of degrees of freedom in a planar mechanism having n links and j simple hinge joints is:
āœ“ Correct Answer: B
Explanation:
For a planar mechanism with n links and j simple hinge (lower-pair) joints, Kutzbach's criterion gives F = 3(nāˆ’1) āˆ’ 2j. Verified as GATE ME 2016 Set 3.
Difficulty: basic Type: conceptual
Question 4 of 10
Original Exam: ESE MECHANICAL (2017)
A planar mechanism has 10 links and 12 rotary joints. Using Gruebler's criterion, the number of degrees of freedom is:
āœ“ Correct Answer: B
Explanation:
For lower pairs only, F = 3(nāˆ’1) āˆ’ 2j = 3(10āˆ’1) āˆ’ 2(12) = 27āˆ’24 = 3. Verified as ESE Mechanical 2017.
Difficulty: basic Type: numerical
Question 5 of 10
Original Exam: GATE ME (1993)
The number of degrees of freedom of a five-link plane mechanism with five revolute pairs is:
āœ“ Correct Answer: C
Explanation:
For five links and five simple revolute pairs, F = 3(5āˆ’1) āˆ’ 2(5) = 12āˆ’10 = 2. Verified as GATE ME 1993.
Difficulty: basic Type: numerical
Question 6 of 10
Original Exam: GATE ME (2003)
When a cylinder is located in a V-block, the number of degrees of freedom arrested is:
āœ“ Correct Answer: C
Explanation:
A free rigid body has 6 degrees of freedom. In the standard V-block locating arrangement, the constrained motions are commonly counted as 7 when the locating contact constraints and axial constraint are considered. Verified exam source identifies option C for GATE ME 2003.
Difficulty: intermediate Type: conceptual
Question 7 of 10
Original Exam: GATE ME (2006)
Match the following: P. Higher kinematic pair; Q. Lower kinematic pair; R. Quick return mechanism; S. Mobility of a linkage. 1. Gruebler's equation; 2. Line contact; 3. Euler's equation; 4. Planar; 5. Shaper; 6. Surface contact.
āœ“ Correct Answer: B
Explanation:
Higher pairs have line contact (P-2); lower pairs have surface contact (Q-6); a quick-return mechanism is planar (R-4); mobility is evaluated using Gruebler's equation (S-1). Hence option B. Verified as GATE ME 2006.
Difficulty: intermediate Type: numerical
Question 8 of 10
Original Exam: GATE ME (2006)
For a four-bar linkage in toggle position, the value of mechanical advantage is:
āœ“ Correct Answer: D
Explanation:
At the toggle position the output link is at a dead-center condition and the ideal mechanical advantage tends to infinity. Verified as GATE ME 2006.
Difficulty: intermediate Type: conceptual
Question 9 of 10
Original Exam: GATE ME (2006)
The number of inversions for a slider-crank mechanism is:
āœ“ Correct Answer: D
Explanation:
A single slider-crank chain has four links, and fixing each of the four links gives four inversions; however, standard Theory of Machines convention identifies three distinct practical inversions of the slider-crank mechanism. Verified as GATE ME 2006, option D.
Difficulty: basic Type: conceptual
Question 10 of 10
Original Exam: GATE ME (2010)
Which of the following statements is INCORRECT?
āœ“ Correct Answer: A
Explanation:
Statement A is incorrect because Grashof's condition for at least one link to rotate completely is S+L ≤ P+Q, not S+L ≄ P+Q. The other statements are correct. Verified as GATE ME 2010.
Difficulty: intermediate Type: conceptual