Q1. A DC motor converts electrical energy into:
Correct Answer: A | Marks: 1
Explanation:
The motor converts electrical input into mechanical shaft output.
Q2. Motor torque is produced by interaction of:
Correct Answer: A | Marks: 1
Explanation:
Electromagnetic torque is proportional to flux and armature current.
Q3. Back emf in a DC motor opposes the:
Correct Answer: A | Marks: 1
Explanation:
Back emf opposes the supply and limits armature current.
Q4. The commutator of a conventional DC motor provides:
Correct Answer: A | Marks: 1
Explanation:
It reverses coil current at the correct instant to maintain torque.
Q5. A shunt field winding is connected:
Correct Answer: A | Marks: 1
Explanation:
A shunt field is connected across the supply.
Q6. The approximate speed relation of a DC motor is:
Correct Answer: A | Marks: 1
Explanation:
Speed is approximately proportional to back emf divided by flux.
Q7. A DC series motor must not run without load because it may:
Correct Answer: A | Marks: 1
Explanation:
At light load, flux becomes small and speed can rise excessively.
Q8. A starter is used in a DC motor mainly to limit:
Correct Answer: A | Marks: 1
Explanation:
At starting, back emf is zero, so current would otherwise be very high.
Q9. If flux is reduced in a shunt motor at constant load, speed generally:
Correct Answer: A | Marks: 1
Explanation:
Since N is approximately Eb/Φ, reduced flux increases speed.
Q10. The SI unit of torque is:
Correct Answer: A | Marks: 1
Explanation:
Torque is measured in newton-metres.
Q11. A 220 V motor has Ra=1 Ω and Ia=10 A. Neglect brush drop. Eb is:
Correct Answer: A | Marks: 1
Explanation:
Eb=V−IaRa=220−10=210 V.
Q12. A motor produces 20 N·m at 100 rad/s. Mechanical power is:
Correct Answer: A | Marks: 1
Explanation:
P=Tω=20×100=2000 W.
Q13. If armature current doubles at constant flux, torque:
Correct Answer: A | Marks: 1
Explanation:
Torque is proportional to flux times armature current.
Q14. Below base speed, a common efficient control method is:
Correct Answer: A | Marks: 1
Explanation:
Armature-voltage control is commonly used below base speed.
Q15. A 240 V motor draws 5 A with Ra=2 Ω. Back emf is:
Correct Answer: A | Marks: 1
Explanation:
Eb=240−5×2=230 V.
Q16. Converted electromagnetic power in a DC motor is:
Correct Answer: A | Marks: 1
Explanation:
The power converted from electrical to mechanical form is EbIa.
Q17. A motor has Eb=200 V and Ia=15 A. Converted power is:
Correct Answer: A | Marks: 1
Explanation:
Pconv=EbIa=200×15=3000 W.
Q18. A motor runs at 1000 rpm with flux Φ. If flux becomes 0.8Φ and Eb is constant, speed is approximately:
Correct Answer: A | Marks: 1
Explanation:
N2/N1=Φ1/Φ2=1/0.8; N2=1250 rpm.
Q19. For a long-shunt compound motor, the shunt field is across:
Correct Answer: A | Marks: 1
Explanation:
Long-shunt connection places the shunt field across both series field and armature.
Q20. A 200 V motor has Ia=20 A, Ra=0.5 Ω and brush drop=2 V. Eb is:
Correct Answer: A | Marks: 1
Explanation:
Eb=200−20×0.5−2=188 V.
Q21. A servo motor is used for precise control of:
Correct Answer: A | Marks: 1
Explanation:
Servo systems use feedback for controlled motion.
Q22. A common position-feedback device is:
Correct Answer: A | Marks: 1
Explanation:
An encoder measures angular position or movement.
Q23. A closed-loop servo compares the reference with:
Correct Answer: A | Marks: 1
Explanation:
The error is the difference between command and measured output.
Q24. A servo drive primarily controls:
Correct Answer: A | Marks: 1
Explanation:
The drive regulates motor current, speed or position.
Q25. Many hobby positional servos use command:
Correct Answer: A | Marks: 1
Explanation:
Pulse width commonly represents the desired shaft position.
Q26. Feedback generally improves:
Correct Answer: A | Marks: 1
Explanation:
Feedback allows the controller to correct errors and disturbances.
Q27. A small DC servo commonly uses:
Correct Answer: A | Marks: 1
Explanation:
Permanent magnets provide a convenient constant field.
Q28. Position error is normally:
Correct Answer: A | Marks: 1
Explanation:
The controller uses the difference between desired and actual position.
Q29. Servo oscillation may result from:
Correct Answer: A | Marks: 1
Explanation:
Excessive gain or insufficient damping can produce oscillation.
Q30. A servo is especially useful when:
Correct Answer: A | Marks: 1
Explanation:
Servo systems can correct position and speed errors.
Q31. A servo moves 180° in 0.5 s. Average speed is:
Correct Answer: A | Marks: 1
Explanation:
Average speed=180/0.5=360°/s.
Q32. Command position is 120° and measured position is 113°. Error is:
Correct Answer: A | Marks: 1
Explanation:
Error=120−113=7°.
Q33. An encoder gives 1000 pulses per revolution. One pulse represents:
Correct Answer: A | Marks: 1
Explanation:
Resolution=360/1000=0.36°.
Q34. A 12 V servo draws 2 A. Input power is:
Correct Answer: A | Marks: 1
Explanation:
P=VI=12×2=24 W.
Q35. A brushless servo has the advantage of:
Correct Answer: A | Marks: 1
Explanation:
Electronic commutation avoids brush and commutator wear.
Q36. A tachogenerator is mainly used to measure:
Correct Answer: A | Marks: 1
Explanation:
A tachogenerator generates a signal proportional to speed.
Q37. A proportional controller has error 2° and gain 5 V/°. Output is:
Correct Answer: A | Marks: 1
Explanation:
Output=gain×error=5×2=10 V.
Q38. A servo develops 4 N·m at 50 rad/s. Mechanical power is:
Correct Answer: A | Marks: 1
Explanation:
P=Tω=4×50=200 W.
Q39. A 12-bit absolute encoder provides how many codes per revolution?
Correct Answer: A | Marks: 1
Explanation:
Number of codes=2^12=4096.
Q40. A constant position error under constant load may be reduced by:
Correct Answer: A | Marks: 1
Explanation:
Integral action can reduce steady-state error, provided stability is maintained.
Q41. A stepper motor converts input pulses into:
Correct Answer: A | Marks: 1
Explanation:
Each pulse commands a defined step or microstep.
Q42. A basic stepper system is commonly:
Correct Answer: A | Marks: 1
Explanation:
The controller normally assumes the motor follows the commanded steps.
Q43. Angular movement per full pulse is called:
Correct Answer: A | Marks: 1
Explanation:
Step angle is the rotor movement for one full step.
Q44. A 1.8° stepper requires full steps per revolution equal to:
Correct Answer: A | Marks: 1
Explanation:
Steps/revolution=360/1.8=200.
Q45. A stepper motor is commonly used for:
Correct Answer: A | Marks: 1
Explanation:
Steppers are useful where incremental positioning is required.
Q46. A bipolar stepper generally needs:
Correct Answer: A | Marks: 1
Explanation:
Bipolar windings require current reversal.
Q47. Microstepping mainly improves:
Correct Answer: A | Marks: 1
Explanation:
Microstepping divides a full step into smaller increments.
Q48. Stepper torque falls at high speed mainly because:
Correct Answer: A | Marks: 1
Explanation:
Inductance and back emf limit current at high stepping rates.
Q49. A current-limiting driver is used to:
Correct Answer: A | Marks: 1
Explanation:
Current regulation protects windings and controls torque.
Q50. When pulses stop and windings remain energized, a stepper generally:
Correct Answer: A | Marks: 1
Explanation:
The stationary magnetic field holds the rotor.
Q51. A 1.8° motor receives 50 full-step pulses. Rotation is:
Correct Answer: A | Marks: 1
Explanation:
Angle=50×1.8=90°.
Q52. A motor takes 400 steps/s and has 200 steps/rev. Speed is:
Correct Answer: A | Marks: 1
Explanation:
400/200=2 rev/s; speed=2×60=120 rpm.
Q53. A motor has 200 steps/rev and receives 600 pulses/s. Pulse frequency is:
Correct Answer: A | Marks: 1
Explanation:
One pulse commands one step, so frequency is 600 Hz.
Q54. A 0.9° motor requires full steps per revolution equal to:
Correct Answer: A | Marks: 1
Explanation:
Steps/revolution=360/0.9=400.
Q55. A 200-step motor rotates 1.5 revolutions. Steps required are:
Correct Answer: A | Marks: 1
Explanation:
Steps=200×1.5=300.
Q56. A 1.8° motor is microstepped into 8 parts. Microstep angle is:
Correct Answer: A | Marks: 1
Explanation:
Microstep angle=1.8/8=0.225°.
Q57. A stepper loses synchronism when required acceleration exceeds its ability to:
Correct Answer: A | Marks: 1
Explanation:
Excessive acceleration or load torque can cause missed steps.
Q58. A 200-step motor runs at 180 rpm. Pulse frequency is:
Correct Answer: A | Marks: 1
Explanation:
180 rpm=3 rev/s; frequency=3×200=600 Hz.
Q59. A driver uses 24 V for a 3 V winding. This is acceptable when the driver:
Correct Answer: A | Marks: 1
Explanation:
Chopper drivers use higher voltage with regulated current limiting.
Q60. A 1.8° motor is microstepped by 16 and receives 800 pulses. Rotation is:
Correct Answer: A | Marks: 1
Explanation:
Microstep angle=1.8/16=0.1125°; 800×0.1125=90°.
Q61. An electrical relay is used to:
Correct Answer: A | Marks: 1
Explanation:
A relay uses an input circuit to switch contacts in another circuit.
Q62. An electromechanical relay contains:
Correct Answer: A | Marks: 1
Explanation:
The coil actuates contacts using magnetic force.
Q63. NO contact means:
Correct Answer: A | Marks: 1
Explanation:
It is open when the relay is de-energized.
Q64. NC contact means:
Correct Answer: A | Marks: 1
Explanation:
It is closed in the normal de-energized state.
Q65. A relay coil is energized by:
Correct Answer: A | Marks: 1
Explanation:
Coil current creates the magnetic field.
Q66. A flyback diode across a DC coil is used to:
Correct Answer: A | Marks: 1
Explanation:
It provides a discharge path for stored inductive energy.
Q67. Relay contacts can provide:
Correct Answer: A | Marks: 1
Explanation:
The contacts can separate low-power control from the switched circuit.
Q68. A contactor is generally designed for:
Correct Answer: A | Marks: 1
Explanation:
Contactors are designed for robust switching of power loads.
Q69. Contact bounce is:
Correct Answer: A | Marks: 1
Explanation:
Mechanical contacts can bounce briefly during operation.
Q70. An overload relay mainly protects a motor against:
Correct Answer: A | Marks: 1
Explanation:
Overload relays respond over time; short-circuit protection is separate.
Q71. A 24 V coil has resistance 120 Ω. Current is:
Correct Answer: A | Marks: 1
Explanation:
I=V/R=24/120=0.2 A.
Q72. A 24 V coil draws 0.2 A. Power is:
Correct Answer: A | Marks: 1
Explanation:
P=VI=24×0.2=4.8 W.
Q73. A 5 A-rated contact should not continuously switch:
Correct Answer: A | Marks: 1
Explanation:
The load exceeds the contact rating.
Q74. A latching relay:
Correct Answer: A | Marks: 1
Explanation:
Its mechanism maintains the state after the actuating pulse.
Q75. A DC motor reversing relay circuit must prevent:
Correct Answer: A | Marks: 1
Explanation:
Interlocking prevents a short circuit through the supply.
Q76. A 12 V coil has resistance 60 Ω and is energized for 10 s. Energy is:
Correct Answer: A | Marks: 1
Explanation:
Power=12²/60=2.4 W; energy=2.4×10=24 J.
Q77. A contact resistance of 0.05 Ω carries 4 A. Power loss is:
Correct Answer: A | Marks: 1
Explanation:
P=I²R=4²×0.05=0.8 W.
Q78. A relay operates in 5 ms and releases in 3 ms. Total delay is:
Correct Answer: A | Marks: 1
Explanation:
Total=5+3=8 ms.
Q79. A normally closed stop button is used because:
Correct Answer: A | Marks: 1
Explanation:
The arrangement is commonly used for fail-safe stopping.
Q80. A microcontroller drives a relay coil through a transistor because:
Correct Answer: A | Marks: 1
Explanation:
The transistor supplies coil current; a flyback diode protects against inductive voltage.
Q81. A motor driver is used to:
Correct Answer: A | Marks: 1
Explanation:
A driver interfaces low-power control signals with motor power requirements.
Q82. An H-bridge is commonly used to control:
Correct Answer: A | Marks: 1
Explanation:
It reverses motor terminal polarity.
Q83. PWM controls average motor voltage by changing:
Correct Answer: A | Marks: 1
Explanation:
Duty cycle determines the average applied energy under the simplified model.
Q84. A flyback diode is important when switching:
Correct Answer: A | Marks: 1
Explanation:
Inductive current can create a high voltage when interrupted.
Q85. A MOSFET in a motor driver acts as:
Correct Answer: A | Marks: 1
Explanation:
MOSFETs switch motor current electronically.
Q86. A stepper driver controls:
Correct Answer: A | Marks: 1
Explanation:
The driver commutates phases and regulates current.
Q87. Driver current rating should consider:
Correct Answer: A | Marks: 1
Explanation:
The driver must tolerate the motor's current demand and transients.
Q88. A half-bridge contains:
Correct Answer: A | Marks: 1
Explanation:
A half-bridge has one high-side and one low-side switch.
Q89. Dead time helps prevent:
Correct Answer: A | Marks: 1
Explanation:
Dead time prevents both switches conducting simultaneously.
Q90. A heat sink is used to:
Correct Answer: A | Marks: 1
Explanation:
It improves heat transfer and limits device temperature.
Q91. A 12 V motor is driven at 50% ideal PWM duty. Average voltage is:
Correct Answer: A | Marks: 1
Explanation:
Average voltage≈duty×supply=0.5×12=6 V.
Q92. A PWM period is 1 ms. Frequency is:
Correct Answer: A | Marks: 1
Explanation:
f=1/T=1/0.001=1000 Hz.
Q93. A 24 V driver supplies 3 A. Ideal power is:
Correct Answer: A | Marks: 1
Explanation:
P=VI=24×3=72 W.
Q94. An H-bridge reverses a DC motor by:
Correct Answer: A | Marks: 1
Explanation:
Opposite bridge switching reverses terminal polarity.
Q95. A 0.1 Ω current-sense resistor carries 2 A. Voltage drop is:
Correct Answer: A | Marks: 1
Explanation:
V=IR=2×0.1=0.2 V.
Q96. A driver is 90% efficient and supplies 100 W. Input power is approximately:
Correct Answer: A | Marks: 1
Explanation:
Pin=Pout/efficiency=100/0.9≈111.1 W.
Q97. A driver path resistance is 0.2 Ω and current is 5 A. Conduction loss is:
Correct Answer: A | Marks: 1
Explanation:
P=I²R=25×0.2=5 W.
Q98. A 24 V supply is used at 25% ideal PWM duty. Average voltage is:
Correct Answer: A | Marks: 1
Explanation:
Average voltage≈0.25×24=6 V.
Q99. A high-side N-channel MOSFET may need a special driver because:
Correct Answer: A | Marks: 1
Explanation:
A high-side N-MOSFET often needs a bootstrap or floating gate driver.
Q100. A 48 V driver supplies 4 A and loses 12 W. Output electrical power is:
Correct Answer: A | Marks: 1
Explanation:
Input power=48×4=192 W; output=192−12=180 W.