Q1. The primary purpose of an engineering drawing is to:
Correct Answer: A | Marks: 1
Explanation:
It communicates geometry, dimensions, tolerances and manufacturing information accurately.
Q2. Which line type is normally used for visible outlines?
Correct Answer: B | Marks: 1
Explanation:
Visible edges are represented by continuous thick lines in standard engineering drawing practice.
Q3. Hidden edges are generally represented by:
Correct Answer: C | Marks: 1
Explanation:
Dashed thin lines indicate edges that are not directly visible.
Q4. Centre lines are commonly represented by:
Correct Answer: D | Marks: 1
Explanation:
Centre lines use thin chain line convention to identify axes and centres.
Q5. A dimension line normally terminates in:
Correct Answer: A | Marks: 1
Explanation:
Arrowheads define the limits of the dimension being indicated.
Q6. The representative fraction (RF) of a scale is:
Correct Answer: B | Marks: 1
Explanation:
RF is the ratio of drawing length to corresponding actual length in the same units.
Q7. A scale with RF less than 1 is called a:
Correct Answer: C | Marks: 1
Explanation:
RF below unity means the drawing is smaller than the actual object.
Q8. Which instrument is primarily used to draw circles and arcs?
Correct Answer: D | Marks: 1
Explanation:
A compass is designed to draw circles and circular arcs.
Q9. The standard reference line separating HP and VP is called:
Correct Answer: A | Marks: 1
Explanation:
The XY reference line represents the intersection of the horizontal and vertical planes.
Q10. A dimension written without a unit in a metric drawing is generally understood as:
Correct Answer: B | Marks: 1
Explanation:
Engineering drawings commonly use millimetres unless another unit is specified.
Q11. The perpendicular bisector of a line segment passes through its:
Correct Answer: C | Marks: 1
Explanation:
Every point on a perpendicular bisector is equidistant from the segment endpoints; it passes through the midpoint.
Q12. To bisect an angle using compass construction, arcs are first drawn from the:
Correct Answer: D | Marks: 1
Explanation:
An arc centred at the angle vertex cuts both arms; equal arcs then locate the bisector.
Q13. A regular hexagon inscribed in a circle has each side equal to the:
Correct Answer: A | Marks: 1
Explanation:
For a regular hexagon, each side subtends 60° and equals the circle radius.
Q14. The sum of interior angles of a quadrilateral is:
Correct Answer: B | Marks: 1
Explanation:
A quadrilateral can be divided into two triangles, giving 2 × 180° = 360°.
Q15. The interior angle of a regular pentagon is:
Correct Answer: C | Marks: 1
Explanation:
Interior angle = (n−2)180°/n = 3×180°/5 = 108°.
Q16. A tangent to a circle is perpendicular to the:
Correct Answer: D | Marks: 1
Explanation:
The radius drawn to the point of contact is normal to the tangent.
Q17. An ellipse has eccentricity:
Correct Answer: A | Marks: 1
Explanation:
For an ellipse, eccentricity e is less than one.
Q18. A parabola is defined by eccentricity equal to:
Correct Answer: B | Marks: 1
Explanation:
A parabola has equal distances from its focus and directrix, hence e = 1.
Q19. The locus of a point equidistant from a fixed point is a:
Correct Answer: C | Marks: 1
Explanation:
A circle is the locus of points at a constant distance from a fixed centre.
Q20. The involute of a circle can be generated by:
Correct Answer: D | Marks: 1
Explanation:
An involute is traced by the endpoint of a taut string as it is unwound from a base curve.
Q21. In orthographic projection, projectors are:
Correct Answer: A | Marks: 1
Explanation:
Orthographic projectors are parallel to one another and normal to the projection plane.
Q22. A point above HP and in front of VP lies in the:
Correct Answer: B | Marks: 1
Explanation:
Above HP and in front of VP defines the first quadrant.
Q23. For a point in the first quadrant, its front view is located:
Correct Answer: C | Marks: 1
Explanation:
A point above HP projects above XY in the front view.
Q24. For a point in the first quadrant, its top view is located:
Correct Answer: D | Marks: 1
Explanation:
A point in front of VP has its top view below XY in first-angle convention.
Q25. A point below HP and behind VP lies in the:
Correct Answer: A | Marks: 1
Explanation:
Below HP and behind VP corresponds to the third quadrant.
Q26. The distance of a point from HP is represented in its:
Correct Answer: B | Marks: 1
Explanation:
The front view shows the height or distance from HP.
Q27. The distance of a point from VP is represented in its:
Correct Answer: C | Marks: 1
Explanation:
The top view represents the distance from VP.
Q28. The locus of the front view of a point at constant height is:
Correct Answer: D | Marks: 1
Explanation:
Constant height keeps the front-view distance from XY constant, producing a parallel locus.
Q29. The two views of a point are connected by:
Correct Answer: A | Marks: 1
Explanation:
Front and top views of the same point lie on the same projector.
Q30. A point on HP has its front view:
Correct Answer: B | Marks: 1
Explanation:
Points on HP have zero height, so their front views lie on XY.
Q31. A line parallel to HP and inclined to VP shows true length in:
Correct Answer: C | Marks: 1
Explanation:
A line parallel to HP is not foreshortened in top view.
Q32. A line parallel to VP and inclined to HP shows true length in:
Correct Answer: D | Marks: 1
Explanation:
A line parallel to VP is represented at true length in front view.
Q33. A line perpendicular to HP appears as a:
Correct Answer: A | Marks: 1
Explanation:
All points have the same top-view location when the line is normal to HP.
Q34. A line perpendicular to VP appears as a:
Correct Answer: B | Marks: 1
Explanation:
All points of a line normal to VP project to one point in front view.
Q35. If a line is parallel to both HP and VP, its projections are:
Correct Answer: C | Marks: 1
Explanation:
The line is parallel to both reference planes, so both principal views show true length.
Q36. The apparent length of an inclined line is generally:
Correct Answer: D | Marks: 1
Explanation:
Projection causes foreshortening; it cannot exceed true length.
Q37. The angle made by a line with HP is called its:
Correct Answer: A | Marks: 1
Explanation:
The true inclination is the angle between the line and HP.
Q38. To obtain the true length of a line inclined to both HP and VP, one may use:
Correct Answer: B | Marks: 1
Explanation:
Rotation and auxiliary projection methods reveal the true length.
Q39. The horizontal trace of a line is the point where it meets:
Correct Answer: C | Marks: 1
Explanation:
The horizontal trace is the intersection of the line with HP.
Q40. The vertical trace of a line is the point where it meets:
Correct Answer: D | Marks: 1
Explanation:
The vertical trace is the intersection of the line with VP.
Q41. A plane parallel to HP appears in true shape in:
Correct Answer: A | Marks: 1
Explanation:
A plane parallel to HP is not foreshortened in its top projection.
Q42. A plane parallel to VP appears in true shape in:
Correct Answer: B | Marks: 1
Explanation:
A plane parallel to VP is seen in true shape in front view.
Q43. A plane perpendicular to HP appears as an:
Correct Answer: C | Marks: 1
Explanation:
A plane normal to HP projects as a line in top view.
Q44. A plane inclined to HP and perpendicular to VP appears as a line in:
Correct Answer: D | Marks: 1
Explanation:
Perpendicularity to VP makes the front projection an edge view.
Q45. The true shape of an inclined plane is obtained using:
Correct Answer: A | Marks: 1
Explanation:
Auxiliary or rotational methods place the plane parallel to a projection plane.
Q46. A circular lamina parallel to HP appears in front view as a:
Correct Answer: B | Marks: 1
Explanation:
Its front projection is an edge view, represented by a line equal to the diameter.
Q47. A circular lamina parallel to VP appears in top view as a:
Correct Answer: C | Marks: 1
Explanation:
Its top projection is an edge view.
Q48. The apparent shape of a plane inclined to the projection plane is generally:
Correct Answer: D | Marks: 1
Explanation:
Inclination reduces the projected area and causes foreshortening.
Q49. A plane having no inclination to HP is:
Correct Answer: A | Marks: 1
Explanation:
Zero inclination to HP means parallelism with HP.
Q50. A plane perpendicular to both HP and VP is parallel to:
Correct Answer: B | Marks: 1
Explanation:
A plane normal to HP and VP is parallel to the profile plane.
Q51. A solid with two equal and parallel polygonal ends is a:
Correct Answer: C | Marks: 1
Explanation:
A prism has equal, parallel bases connected by lateral faces.
Q52. A solid with one polygonal base and triangular faces meeting at a vertex is a:
Correct Answer: D | Marks: 1
Explanation:
A pyramid has a base and triangular lateral faces converging at an apex.
Q53. A cylinder is generated by moving a:
Correct Answer: A | Marks: 1
Explanation:
A right circular cylinder can be viewed as a rectangle revolved about one of its sides.
Q54. A cone has:
Correct Answer: B | Marks: 1
Explanation:
A cone consists of one circular base and a single apex.
Q55. When the axis of a cylinder is perpendicular to HP, its top view is generally a:
Correct Answer: C | Marks: 1
Explanation:
The circular base is parallel to HP and appears in true shape.
Q56. When the axis of a prism is perpendicular to HP, its top view shows the:
Correct Answer: D | Marks: 1
Explanation:
The base is parallel to HP and is seen in true shape.
Q57. For a solid resting on HP, the contact points with HP are shown in:
Correct Answer: A | Marks: 1
Explanation:
The top view represents the footprint and orientation of the base on HP.
Q58. A solid of revolution is generated by revolving a plane area about:
Correct Answer: B | Marks: 1
Explanation:
Revolution of a plane area around an axis produces a solid of revolution.
Q59. The axis of a right circular cone passes through:
Correct Answer: C | Marks: 1
Explanation:
The cone axis joins the apex to the centre of its circular base.
Q60. In projection of solids, the first step for an inclined axis is commonly to draw:
Correct Answer: D | Marks: 1
Explanation:
The simple-position view is used before rotating the solid to the required inclination.
Q61. The angle between any two isometric axes is:
Correct Answer: A | Marks: 1
Explanation:
The three isometric axes are separated by 120° in the plane of the drawing.
Q62. The two receding isometric axes are usually drawn at:
Correct Answer: B | Marks: 1
Explanation:
The left and right isometric axes are conventionally inclined 30° to the horizontal.
Q63. In true isometric projection, lengths are:
Correct Answer: C | Marks: 1
Explanation:
All three principal directions have the same isometric foreshortening.
Q64. An isometric scale is used to:
Correct Answer: D | Marks: 1
Explanation:
The isometric scale gives the reduced lengths used in isometric projection.
Q65. In an isometric view (not projection), measurements along isometric axes are generally:
Correct Answer: A | Marks: 1
Explanation:
An isometric view is commonly drawn using true lengths, unlike an isometric projection.
Q66. A circle on an isometric plane is represented approximately by a(n):
Correct Answer: B | Marks: 1
Explanation:
A circle appears as an ellipse when viewed obliquely in isometric representation.
Q67. A vertical edge in an isometric drawing is normally drawn:
Correct Answer: C | Marks: 1
Explanation:
Vertical edges remain vertical in standard isometric drawing.
Q68. A line parallel to one of the isometric axes is called:
Correct Answer: D | Marks: 1
Explanation:
Lines parallel to the three isometric axes are isometric lines.
Q69. A line not parallel to any isometric axis is called:
Correct Answer: A | Marks: 1
Explanation:
Non-isometric lines require coordinate or end-point methods for construction.
Q70. For a cube in isometric projection, the visible faces are generally:
Correct Answer: B | Marks: 1
Explanation:
The three visible square faces project as equal parallelogram-like faces.
Q71. In first-angle projection, the object is located:
Correct Answer: C | Marks: 1
Explanation:
First-angle projection places the object between the observer and the projection plane.
Q72. In third-angle projection, the projection plane is located:
Correct Answer: D | Marks: 1
Explanation:
Third-angle projection places the plane between the observer and object.
Q73. In first-angle projection, the top view is placed:
Correct Answer: A | Marks: 1
Explanation:
After rotating HP downward, the top view appears below the front view.
Q74. In third-angle projection, the top view is placed:
Correct Answer: B | Marks: 1
Explanation:
In third-angle projection, the top view is placed above the front view.
Q75. In first-angle projection, the right-side view is placed:
Correct Answer: C | Marks: 1
Explanation:
The side-view positions are reversed relative to the viewing direction in first-angle projection.
Q76. In third-angle projection, the right-side view is placed:
Correct Answer: D | Marks: 1
Explanation:
Third-angle projection places the right-side view on the right.
Q77. The projection method commonly used in India for engineering drawings is:
Correct Answer: A | Marks: 1
Explanation:
First-angle projection is widely prescribed in Indian engineering drawing practice.
Q78. The symbol for orthographic projection convention is used to indicate:
Correct Answer: B | Marks: 1
Explanation:
The frustum-and-circle symbol identifies first-angle or third-angle convention.
Q79. In first-angle projection, the left-side view is placed:
Correct Answer: C | Marks: 1
Explanation:
First-angle projection reverses the side-view placement.
Q80. A major reason for specifying first- or third-angle projection is to:
Correct Answer: D | Marks: 1
Explanation:
The convention ensures that users interpret view positions consistently.
Q81. A line of true length 100 mm makes 30° with HP and is parallel to VP. Its front-view length is:
Correct Answer: A | Marks: 1
Explanation:
Because the line is parallel to VP, its front view shows true length.
Q82. A line of true length 100 mm makes 30° with VP and is parallel to HP. Its top-view length is:
Correct Answer: B | Marks: 1
Explanation:
Because the line is parallel to HP, its top view shows true length.
Q83. The projection of a 100 mm line inclined at 30° to the projection plane has length:
Correct Answer: C | Marks: 1
Explanation:
Projected length = true length × cos 30° = 100 × 0.866 = 86.6 mm.
Q84. The projection of a 100 mm line inclined at 60° to the projection plane has length:
Correct Answer: D | Marks: 1
Explanation:
Projected length = 100 × cos 60° = 50 mm.
Q85. A regular polygon has each exterior angle equal to 45°. Number of sides is:
Correct Answer: A | Marks: 1
Explanation:
Number of sides = 360°/45° = 8.
Q86. The interior angle of a regular hexagon is:
Correct Answer: B | Marks: 1
Explanation:
Interior angle = (6−2)×180°/6 = 120°.
Q87. A circle of diameter 40 mm is drawn at true scale. Its radius is:
Correct Answer: C | Marks: 1
Explanation:
Radius is half the diameter: 40/2 = 20 mm.
Q88. For a cylinder of radius 20 mm, the circumference used in lateral development is approximately:
Correct Answer: D | Marks: 1
Explanation:
Circumference = 2πr = 2π×20 ≈ 125.66 mm.
Q89. The area of a rectangle 80 mm × 50 mm is:
Correct Answer: A | Marks: 1
Explanation:
Area = length × breadth = 80×50 = 4000 mm².
Q90. If a drawing length is 25 mm and actual length is 100 mm, RF is:
Correct Answer: B | Marks: 1
Explanation:
RF = drawing length/actual length = 25/100 = 1/4.
Q91. Which pencil grade is generally harder and produces a lighter line?
Correct Answer: C | Marks: 1
Explanation:
H-grade pencils are harder and produce lighter, finer lines.
Q92. A leader line is used primarily to:
Correct Answer: D | Marks: 1
Explanation:
Leader lines connect explanatory text or dimensions to the relevant feature.
Q93. The exterior angle of a regular octagon is:
Correct Answer: A | Marks: 1
Explanation:
Exterior angle = 360°/8 = 45°.
Q94. A regular triangle constructed with a compass has each interior angle equal to:
Correct Answer: B | Marks: 1
Explanation:
All angles of an equilateral triangle are 60°.
Q95. A point behind VP has its top view located:
Correct Answer: C | Marks: 1
Explanation:
Behind VP places the top view above XY under the usual first-angle convention.
Q96. If a line is parallel to HP, its front view is:
Correct Answer: D | Marks: 1
Explanation:
All points of a line parallel to HP have the same height, so the front view is parallel to XY.
Q97. A plane parallel to the profile plane appears in true shape in:
Correct Answer: A | Marks: 1
Explanation:
A profile-plane-parallel plane is seen without foreshortening in the side view.
Q98. The top view of a sphere in orthographic projection is a:
Correct Answer: B | Marks: 1
Explanation:
A sphere projects as a circle of diameter equal to its true diameter in every principal view.
Q99. Hidden edges in an isometric drawing, when required, are represented using:
Correct Answer: C | Marks: 1
Explanation:
Hidden features follow the hidden-line convention even in an isometric drawing.
Q100. In third-angle projection, the left-side view is placed:
Correct Answer: D | Marks: 1
Explanation:
Third-angle projection places each side view on the same side as the viewing direction.